[leetcode] 110. Balanced Binary Tree
2023. 3. 13. 13:15ㆍ노트/Algorithm : 알고리즘
Givin a binary tree, determine if it is
.
Example 1:
Input: root = [3,9,20,null,null,15,7]
Output: true
Example 2:
Input: root = [1,2,2,3,3,null,null,4,4]
Output: false
Example 3:
Input: root = []
Output: true
Constraints:
- The number of nodes in the tree is in the range [0, 5000].
- -104 <= Node.val <= 104
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def isBalanced(self, root: Optional[TreeNode]) -> bool:
def check(root):
if not root:
return 0
left = check(root.left)
right = check(root.right)
if left == -1 or right == -1 or abs(left - right) > 1:
return -1
return max(left, right) + 1
return check(root) != -1
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