[leetcode] 743. Network Delay Time

2023. 2. 22. 11:14노트/Algorithm : 알고리즘

You are given a network of n nodes, labeled from 1 to n. You are also given times, a list of travel times as directed edges times[i] = (ui, vi, wi), where ui is the source node, vi is the target node, and wi is the time it takes for a signal to travel from source to target.

We will send a signal from a given node k. Return the minimum time it takes for all the n nodes to receive the signal. If it is impossible for all the n nodes to receive the signal, return -1.

 

Example 1:

Input: times = [[2,1,1],[2,3,1],[3,4,1]], n = 4, k = 2
Output: 2

Example 2:

Input: times = [[1,2,1]], n = 2, k = 1
Output: 1

Example 3:

Input: times = [[1,2,1]], n = 2, k = 2
Output: -1

 

Constraints:

  • 1 <= k <= n <= 100
  • 1 <= times.length <= 6000
  • times[i].length == 3
  • 1 <= ui, vi <= n
  • ui != vi
  • 0 <= wi <= 100
  • All the pairs (ui, vi) are unique. (i.e., no multiple edges.)
class Solution(object):
    def networkDelayTime(self, times, n, k):
        """
        :type times: List[List[int]]
        :type n: int
        :type k: int
        :rtype: int
        """
        graph = collections.defaultdict(list)
        # 그래프 인접 리스트 구성 
        for u, v, w in times:
            graph[u].append((v,w))

        # 큐 변수: [(소요시간, 정점)]
        Q = [(0, k)]
        dist = collections.defaultdict(int)

        while Q:
            time, node = heapq.heappop(Q)
            if node not in dist:
                dist[node] = time
                for v,w in graph[node]:
                    alt = time + w 
                    heapq.heappush(Q, (alt, v))

        # 모든 노드의 최단 경로 존재 여부 판별 
        if len(dist) == n:
            return max(dist.values())

        return -1